Finding out [Minutes][Seconds.X]

Sample output :
[Minutes][Seconds.X]
[23][27.6]

//PS:93
scala> // c220 > a15

scala> import java.util.Calendar
import java.util.Calendar

scala> import java.text.SimpleDateFormat
import java.text.SimpleDateFormat

scala> val now = Calendar.getInstance().getTime()
now: java.util.Date = Sat Apr 30 19:23:27 EDT 2016

scala> val myFormat = new SimpleDateFormat("mm.ss.SS")
myFormat: java.text.SimpleDateFormat = java.text.SimpleDateFormat@15efcee0

scala> val minNmillisec = myFormat.format(now)
minNmillisec: String = 23.27.636

// Use regex '.'
scala> val splitted = minNmillisec.split("\\.")
splitted: Array[String] = Array(23, 27, 636)

scala> val min = splitted(0)
min: String = 23

scala> val sec = splitted(1)
sec: String = 27

scala> val millisec = splitted(2)
millisec: String = 636

scala> val millisecTruncated = millisec(0)
millisecTruncated: Char = 6

// Format string using String Interpolation (s/f/raw)
scala> val result = f"[$min%2s][$sec%2s.$millisecTruncated%s]"
result: String = [23][27.6]